What is wrong with this code????

Hello... Is the MULTIQUOTE button... Im using sprite CSS:

1. An image in normal mode - CSS SPRITE
2. An image when mouse is over the button - CSS SPRITE
3. An image when button is clicked - A simple .gif

MY CODE, something is wrong... I dont know where:

PHP Code:

<if condition="$show['multiquote_post']">
<a href="$post[replylink]" rel="nofollow" onclick="return false" class="multiquote spritebutton">
<if condition="$show['multiquote_selected']">
<img src="$stylevar[imgdir_button]/multiquote_on.gif"</if>alt="$vbphrase[multi_quote_this_message]" border="0" id="mq_$post[postid]" />
</a>
</if> 


DEFAULT code:

PHP Code:

<if condition="$show['multiquote_post']">
<a href="$post[replylink]" rel="nofollow" onclick="return false">
<img src="$stylevar[imgdir_button]/multiquote_<if condition="$show['multiquote_selected']">on<else />off</if>.gif" alt="$vbphrase[multi_quote_this_message]" border="0" id="mq_$post[postid]" />
</a>
</if> 


In the first block, your last /if is in the wrong spot.

try:

Code:

<if condition="$show['multiquote_post']">
<a href="$post[replylink]" rel="nofollow" onclick="return false" class="multiquote spritebutton">
<if condition="$show['multiquote_selected']">
<img src="$stylevar[imgdir_button]/multiquote_on.gif" alt="$vbphrase[multi_quote_this_message]" border="0" id="mq_$post[postid]" /></if>
</a>
</if>  

Thanks Brian.

With your code:

1. An image in normal mode - OK
2. An image when mouse is over the button - OK
3. An image when button is clicked - When I click the button nothing happend.

You're missing the condition for on/off state

<img src="$stylevar[imgdir_button]/multiquote_<if condition="$show['multiquote_selected']">on<else />off</if>.gif" alt="$vbphrase[multi_quote_this_message]" border="0" id="mq_$post[postid]" />